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avno 1

avno 1

7661 Popeye avno 1 1 and Theorem 2 Proof of Lemma 1 Introduce an auxiliary operator A1 = Ax Avno - 1 ) > 0 , no avno 1 Avno ) d2 - Avn2 do - Avno 1- AvVF Vin = 0 We next further shorten the notation in to VF Vin = n3s3 + n2s2 + n1s + no d3s3 + d2s2 + d1s + do

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